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Nickelodeon (ended 2008)

Motivational Posters on DA

  • Avatar of DeeDuck33

    DeeDuck33

    [501]Apr 30, 2008
    • member since: 04/15/08
    • level: 11
    • rank: Red Shirted Lt.
    • posts: 1,198
    daveshanFromGMU wrote:

    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.

    Math, it burns!

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  • Avatar of someone198

    someone198

    [502]Apr 30, 2008
    • member since: 06/08/05
    • level: 27
    • rank: Shark Jumper
    • posts: 1,144

    daveshanFromGMU wrote:

    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.

    Sorry, incorrect.

    tomtitan wrote:

    Easy:
    1: Turn it into an ax^2+bx+c=0 format
    7x^2+5x-6

    2: If this were a graph, you need to find what X equals when Y=0. To do that, use the quadratic formula: "negative b plus-or-minus the square root of b squared minus 4ac over 2a" (I cannot for the life of me figure out the right html format to write that as an equation)

    3: Do the math.

    X=.635 and X=-1.350

    Plug them in, and you'll see they fit (approximately; they had to be rounded).

    Thank you!

    Edited on 04/30/2008 5:09pm
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  • Avatar of Spacerac

    Spacerac

    [503]Apr 30, 2008
    • member since: 01/14/08
    • level: 15
    • rank: Ginsu Knife
    • posts: 5,899
    someone198 wrote:
    daveshanFromGMU wrote:
    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.
    Sorry, incorrect.
    tomtitan wrote:
    Easy:1: Turn it into an ax^2+bx+c=0 format

    7x^2+5x-6

    2: If this were a graph, you need to find what X equals when Y=0. To do that, use the quadratic formula: "negative b plus-or-minus the square root of b squared minus 4ac over 2a" (I cannot for the life of me figure out the right html format to write that as an equation)

    3: Do the math.

    X=.635 and X=-1.350

    Plug them in, and you'll see they fit (approximately; they had to be rounded).

    Thank you!
    I was close..

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  • Avatar of Amity_Phantom

    Amity_Phantom

    [504]Apr 30, 2008
    • member since: 04/17/07
    • level: 10
    • rank: Holy Level 10!
    • posts: 2,582
    Spacerac wrote:
    someone198 wrote:
    daveshanFromGMU wrote:
    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.
    Sorry, incorrect.
    tomtitan wrote:
    Easy:1: Turn it into an ax^2+bx+c=0 format

    7x^2+5x-6

    2: If this were a graph, you need to find what X equals when Y=0. To do that, use the quadratic formula: "negative b plus-or-minus the square root of b squared minus 4ac over 2a" (I cannot for the life of me figure out the right html format to write that as an equation)

    3: Do the math.

    X=.635 and X=-1.350

    Plug them in, and you'll see they fit (approximately; they had to be rounded).

    Thank you!
    I was close..

    X= -b+ ll b^2-4ac

    2a

    (The double line is the square root sign, and the underline is a fraction)

    Or something like that.

    Edited on 04/30/2008 5:59pm
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  • Avatar of Valin610

    Valin610

    [505]Apr 30, 2008
    • member since: 01/10/08
    • level: 7
    • rank: Talk Show Host
    • posts: 810
    Or you can use the Quadratic Equation. Don't forget the song!

    "X equals negative b.
    Plus or minus the square root.
    b squared minus 4 a c.
    All over 2 a."
    (Sung like Pop Goes the Weasel)
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  • Avatar of Spacerac

    Spacerac

    [506]Apr 30, 2008
    • member since: 01/14/08
    • level: 15
    • rank: Ginsu Knife
    • posts: 5,899
    Valin610 wrote:
    Or you can use the Quadratic Equation. Don't forget the song!

    "X equals negative b.
    Plus or minus the square root.
    b squared minus 4 a c.
    All over 2 a."
    (Sung like Pop Goes the Weasel)
    I prefer the "try random x values on the calculator method" XD though the Quadratic Equation admittedly works better.
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  • Avatar of someone198

    someone198

    [507]Apr 30, 2008
    • member since: 06/08/05
    • level: 27
    • rank: Shark Jumper
    • posts: 1,144

    A bunch from "The Boiling Rock." Don't click if you don't want to be spoiled.

    http://img170.imageshack.us/img170/5757/95stormtrooperem3.jpg

    http://img514.imageshack.us/img514/2423/94typicalzukoluckhi6.jpg

    http://img170.imageshack.us/img170/2540/96thisisgonnabefunvg4.jpg

    http://img142.imageshack.us/img142/9725/91zukosgirljp1.jpg

    http://img214.imageshack.us/img214/9991/92youmiscalculatednz8.jpg

    obedient minion

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  • Avatar of Eman5805

    Eman5805

    [508]Apr 30, 2008
    • member since: 11/05/04
    • level: 14
    • rank: Autobot
    • posts: 5,943
    I know I aced my final algebra exam, but when the heck did this become the "Discuss Advanced Algebra Motivational Posters on DA" thread?? Because I think someone needs to change the sign, and I need to start steering clear of it...
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  • Avatar of Yourdogsdead

    Yourdogsdead

    [509]Apr 30, 2008
    • member since: 09/15/07
    • level: 4
    • rank: Thighmaster
    • posts: 103
    Eman5805 wrote:
    I know I aced my final algebra exam, but when the heck did this become the "Discuss Advanced Algebra Motivational Posters on DA" thread?? Because I think someone needs to change the sign, and I need to start steering clear of it...


    Good question, i get enough of math at school
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  • Avatar of DeeDuck33

    DeeDuck33

    [510]Apr 30, 2008
    • member since: 04/15/08
    • level: 11
    • rank: Red Shirted Lt.
    • posts: 1,198
    someone198 wrote:

    A bunch from "The Boiling Rock." Don't click if you don't want to be spoiled.

    http://img170.imageshack.us/img170/5757/95stormtrooperem3.jpg

    http://img514.imageshack.us/img514/2423/94typicalzukoluckhi6.jpg

    http://img170.imageshack.us/img170/2540/96thisisgonnabefunvg4.jpg

    http://img142.imageshack.us/img142/9725/91zukosgirljp1.jpg

    http://img214.imageshack.us/img214/9991/92youmiscalculatednz8.jpg

    obedient minion

    Those were great!
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  • Avatar of daveshanFromGMU

    daveshanFromGMU

    [511]Apr 30, 2008
    • member since: 07/27/07
    • level: 8
    • rank: Super-Friend
    • posts: 849
    Where did you get the BR picks?
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  • Avatar of zimtower

    zimtower

    [512]Apr 30, 2008
    • member since: 12/28/03
    • level: 5
    • rank: Caveman Lawyer
    • posts: 271
    Amity_Phantom wrote:
    Spacerac wrote:
    someone198 wrote:
    daveshanFromGMU wrote:
    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.
    Sorry, incorrect.
    tomtitan wrote:
    Easy:1: Turn it into an ax^2+bx+c=0 format

    7x^2+5x-6

    2: If this were a graph, you need to find what X equals when Y=0. To do that, use the quadratic formula: "negative b plus-or-minus the square root of b squared minus 4ac over 2a" (I cannot for the life of me figure out the right html format to write that as an equation)

    3: Do the math.

    X=.635 and X=-1.350

    Plug them in, and you'll see they fit (approximately; they had to be rounded).

    Thank you!
    I was close..

    X= -b+ ll b^2-4ac

    2a

    (The double line is the square root sign, and the underline is a fraction)

    Or something like that.

    Wow these motivational posters really do work!
    You must be registered and logged in to post a message.
  • Avatar of xXKarisuXx

    xXKarisuXx

    [513]Apr 30, 2008
    • member since: 04/10/06
    • level: 12
    • rank: Evil Bert
    • posts: 585
    zimtower wrote:
    Amity_Phantom wrote:
    Spacerac wrote:
    someone198 wrote:
    daveshanFromGMU wrote:
    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.
    Sorry, incorrect.
    tomtitan wrote:
    Easy:1: Turn it into an ax^2+bx+c=0 format

    7x^2+5x-6

    2: If this were a graph, you need to find what X equals when Y=0. To do that, use the quadratic formula: "negative b plus-or-minus the square root of b squared minus 4ac over 2a" (I cannot for the life of me figure out the right html format to write that as an equation)

    3: Do the math.

    X=.635 and X=-1.350

    Plug them in, and you'll see they fit (approximately; they had to be rounded).

    Thank you!
    I was close..

    X= -b+ ll b^2-4ac

    2a

    (The double line is the square root sign, and the underline is a fraction)

    Or something like that.

    Wow these motivational posters really do work!

    I was just about to say, "Hey, I can do that!"
    Though my TI-84 Plus Silver Edition graphing calculator helps as well.
    You must be registered and logged in to post a message.
  • Avatar of SpiffyBacon

    SpiffyBacon

    [514]Apr 30, 2008
    • member since: 01/16/08
    • level: 10
    • rank: Holy Level 10!
    • posts: 454
    xXKarisuXx wrote:
    zimtower wrote:
    Amity_Phantom wrote:
    Spacerac wrote:
    someone198 wrote:
    daveshanFromGMU wrote:
    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.
    Sorry, incorrect.
    tomtitan wrote:
    Easy:1: Turn it into an ax^2+bx+c=0 format

    7x^2+5x-6

    2: If this were a graph, you need to find what X equals when Y=0. To do that, use the quadratic formula: "negative b plus-or-minus the square root of b squared minus 4ac over 2a" (I cannot for the life of me figure out the right html format to write that as an equation)

    3: Do the math.

    X=.635 and X=-1.350

    Plug them in, and you'll see they fit (approximately; they had to be rounded).

    Thank you!
    I was close..

    X= -b+ ll b^2-4ac

    2a

    (The double line is the square root sign, and the underline is a fraction)

    Or something like that.
    Wow these motivational posters really do work!
    I was just about to say, "Hey, I can do that!" Though my TI-84 Plus Silver Edition graphing calculator helps as well.

    Aaah, the algebra crap is good, but that's old. What about parametric equations?

    You must be registered and logged in to post a message.
  • Avatar of daveshanFromGMU

    daveshanFromGMU

    [515]Apr 30, 2008
    • member since: 07/27/07
    • level: 8
    • rank: Super-Friend
    • posts: 849
    SpiffyBacon wrote:
    xXKarisuXx wrote:
    zimtower wrote:
    Amity_Phantom wrote:
    Spacerac wrote:
    someone198 wrote:
    daveshanFromGMU wrote:
    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.
    Sorry, incorrect.
    tomtitan wrote:
    Easy:1: Turn it into an ax^2+bx+c=0 format

    7x^2+5x-6

    2: If this were a graph, you need to find what X equals when Y=0. To do that, use the quadratic formula: "negative b plus-or-minus the square root of b squared minus 4ac over 2a" (I cannot for the life of me figure out the right html format to write that as an equation)

    3: Do the math.

    X=.635 and X=-1.350

    Plug them in, and you'll see they fit (approximately; they had to be rounded).

    Thank you!
    I was close..

    X= -b+ ll b^2-4ac

    2a

    (The double line is the square root sign, and the underline is a fraction)

    Or something like that.
    Wow these motivational posters really do work!
    I was just about to say, "Hey, I can do that!" Though my TI-84 Plus Silver Edition graphing calculator helps as well.

    Aaah, the algebra crap is good, but that's old. What about parametric equations?

    LEAVE PARAMETRIC EQUATIONS ALONE!!!!

    You must be registered and logged in to post a message.
  • Avatar of SpiffyBacon

    SpiffyBacon

    [516]Apr 30, 2008
    • member since: 01/16/08
    • level: 10
    • rank: Holy Level 10!
    • posts: 454
    daveshanFromGMU wrote:
    SpiffyBacon wrote:
    xXKarisuXx wrote:
    zimtower wrote:
    Amity_Phantom wrote:
    Spacerac wrote:
    someone198 wrote:
    daveshanFromGMU wrote:
    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.
    Sorry, incorrect.
    tomtitan wrote:
    Easy:1: Turn it into an ax^2+bx+c=0 format

    7x^2+5x-6

    2: If this were a graph, you need to find what X equals when Y=0. To do that, use the quadratic formula: "negative b plus-or-minus the square root of b squared minus 4ac over 2a" (I cannot for the life of me figure out the right html format to write that as an equation)

    3: Do the math.

    X=.635 and X=-1.350

    Plug them in, and you'll see they fit (approximately; they had to be rounded).

    Thank you!
    I was close..

    X= -b+ ll b^2-4ac

    2a

    (The double line is the square root sign, and the underline is a fraction)

    Or something like that.
    Wow these motivational posters really do work!
    I was just about to say, "Hey, I can do that!" Though my TI-84 Plus Silver Edition graphing calculator helps as well.

    Aaah, the algebra crap is good, but that's old. What about parametric equations?

    LEAVE PARAMETRIC EQUATIONS ALONE!!!!

    Not even as a motovational poster?

    You must be registered and logged in to post a message.
  • Avatar of zimtower

    zimtower

    [517]Apr 30, 2008
    • member since: 12/28/03
    • level: 5
    • rank: Caveman Lawyer
    • posts: 271
    SpiffyBacon wrote:
    daveshanFromGMU wrote:
    SpiffyBacon wrote:
    xXKarisuXx wrote:
    zimtower wrote:
    Amity_Phantom wrote:
    Spacerac wrote:
    someone198 wrote:
    daveshanFromGMU wrote:
    Guys, it comes out to about .70472 or about -1.419. Just plug it in to a graphing calculator and find what X equals when y is 0.
    Sorry, incorrect.
    tomtitan wrote:
    Easy:1: Turn it into an ax^2+bx+c=0 format

    7x^2+5x-6

    2: If this were a graph, you need to find what X equals when Y=0. To do that, use the quadratic formula: "negative b plus-or-minus the square root of b squared minus 4ac over 2a" (I cannot for the life of me figure out the right html format to write that as an equation)

    3: Do the math.

    X=.635 and X=-1.350

    Plug them in, and you'll see they fit (approximately; they had to be rounded).

    Thank you!
    I was close..

    X= -b+ ll b^2-4ac

    2a

    (The double line is the square root sign, and the underline is a fraction)

    Or something like that.
    Wow these motivational posters really do work!
    I was just about to say, "Hey, I can do that!" Though my TI-84 Plus Silver Edition graphing calculator helps as well.

    Aaah, the algebra crap is good, but that's old. What about parametric equations?

    LEAVE PARAMETRIC EQUATIONS ALONE!!!!

    Not even as a motovational poster?
    You must be registered and logged in to post a message.
  • Avatar of daveshanFromGMU

    daveshanFromGMU

    [518]May 1, 2008
    • member since: 07/27/07
    • level: 8
    • rank: Super-Friend
    • posts: 849

    zimtower wrote:

    QFT!

    You must be registered and logged in to post a message.
  • Avatar of Spacerac

    Spacerac

    [519]May 1, 2008
    • member since: 01/14/08
    • level: 15
    • rank: Ginsu Knife
    • posts: 5,899
    DeeDuck33 wrote:
    someone198 wrote:

    A bunch from "The Boiling Rock." Don't click if you don't want to be spoiled.

    http://img170.imageshack.us/img170/5757/95stormtrooperem3.jpg

    http://img514.imageshack.us/img514/2423/94typicalzukoluckhi6.jpg

    http://img170.imageshack.us/img170/2540/96thisisgonnabefunvg4.jpg

    http://img142.imageshack.us/img142/9725/91zukosgirljp1.jpg

    http://img214.imageshack.us/img214/9991/92youmiscalculatednz8.jpg

    obedient minion

    Those were great!
    Agreed. I really like "miscalculated." All your posters are just so... truthful.
    You must be registered and logged in to post a message.
  • Avatar of tomtitan

    tomtitan

    [520]May 1, 2008
    • member since: 03/01/07
    • level: 19
    • rank: Fall Guy
    • posts: 10,891
    All these numbers made my brain hurt.

    Joke is, my maths teacher wasn't in today, so I didn't need to hand it in!
    You must be registered and logged in to post a message.
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